Source code for ufl.permutation

# -*- coding: utf-8 -*-
"""This module provides utility functions for computing permutations
and generating index lists."""

# Copyright (C) 2008-2016 Anders Logg and Kent-Andre Mardal
#
# This file is part of UFL (https://www.fenicsproject.org)
#
# SPDX-License-Identifier:    LGPL-3.0-or-later
#
# Modified by Martin Alnæs 2009-2016


[docs]def compute_indices(shape): "Compute all index combinations for given shape" if len(shape) == 0: return ((),) sub_indices = compute_indices(shape[1:]) indices = [] for i in range(shape[0]): for sub_index in sub_indices: indices.append((i,) + sub_index) return tuple(indices)
# functional version:
[docs]def compute_indices2(shape): "Compute all index combinations for given shape" return ((),) if len(shape) == 0 else tuple((i,) + sub_index for i in range(shape[0]) for sub_index in compute_indices2(shape[1:]))
[docs]def build_component_numbering(shape, symmetry): """Build a numbering of components within the given value shape, taking into consideration a symmetry mapping which leaves the mapping noncontiguous. Returns a dict { component -> numbering } and an ordered list of components [ numbering -> component ]. The dict contains all components while the list only contains the ones not mapped by the symmetry mapping. """ vi2si, si2vi = {}, [] indices = compute_indices(shape) # Number components not in symmetry mapping for c in indices: if c not in symmetry: vi2si[c] = len(si2vi) si2vi.append(c) # Copy numbering to mapped components for c in indices: if c in symmetry: vi2si[c] = vi2si[symmetry[c]] # Validate for k, c in enumerate(si2vi): assert vi2si[c] == k return vi2si, si2vi
[docs]def compute_permutations(k, n, skip=None): """Compute all permutations of k elements from (0, n) in rising order. Any elements that are contained in the list skip are not included. """ if k == 0: return [] if skip is None: skip = [] if k == 1: return [(i,) for i in range(n) if i not in skip] pp = compute_permutations(k - 1, n, skip) permutations = [] for i in range(n): if i in skip: continue for p in pp: if i < p[0]: permutations.append((i,) + p) return permutations
[docs]def compute_permutation_pairs(j, k): """Compute all permutations of j + k elements from (0, j + k) in rising order within (0, j) and (j, j + k) respectively. """ permutations = [] pp0 = compute_permutations(j, j + k) for p0 in pp0: pp1 = compute_permutations(k, j + k, p0) for p1 in pp1: permutations.append((p0, p1)) return permutations
[docs]def compute_sign(permutation): "Compute sign by sorting." sign = 1 n = len(permutation) p = [p for p in permutation] for i in range(n - 1): for j in range(n - 1): if p[j] > p[j + 1]: (p[j], p[j + 1]) = (p[j + 1], p[j]) sign = -sign elif p[j] == p[j + 1]: return 0 return sign
[docs]def compute_order_tuples(k, n): "Compute all tuples of n integers such that the sum is k" if n == 1: return ((k,),) order_tuples = [] for i in range(k + 1): for order_tuple in compute_order_tuples(k - i, n - 1): order_tuples.append(order_tuple + (i,)) return tuple(order_tuples)